2.5: Equilibrium Analysis for Concurrent Force Systems

If a body is in static equilibrium, then by definition that body is not accelerating. If we know that the body is not accelerating then we know that the sum of the forces acting on that body must be equal to zero. This is the basis for equilibrium analysis for a particle. In order to solve for any unknowns in our sum of forces equation, we actually need to turn the one vector equation into a set of scalar equations. For two dimensional problems, we will split our one vector equation down into two scalar equations. We do this by summing up all the \(x\) components of the force vectors and setting them equal to zero in our first equation, and summing up all the \(y\) components of the force vectors and setting them equal to zero in our second equation. \[ \sum \vec \, = \, 0 \] \[ \sum F_x \, = \, 0 \, ; \,\,\, \sum F_y \, = \, 0 \] We do something similar in three dimensional problems except we will break all our force vectors down into \(x\), \(y\), and \(z\) components, setting the sum of \(x\) components equal to zero for our first equation, the sum of all the \(y\) components equal to zero for our second equation, and the sum of all our \(z\) components equal to zero for our third equation. \[ \sum \vec \, = \, 0 \] \[ \sum F_x \, = \, 0 \, ; \,\,\, \sum F_y \, = \, 0 \, ; \,\,\, \sum F_z \, = \, 0 \] Once we have written out the equilibrium equations, we can solve the equations for any unknown forces.

Finding the Equilibrium Equations:

The first step in finding the equilibrium equations is to draw a free body diagram of the body being analyzed. This diagram should show all the known and unknown force vectors acting on the body. In the free body diagram, provide values for any of the know magnitudes or directions for the force vectors and provide variable names for any unknowns (either magnitudes or directions). Example of reducing the picture accompanying with a force analysis problem into a free body diagram.Next you will need to chose the \(x\), \(y\), and \(z\) axes. These axes do need to be perpendicular to one another, but they do not necessarily have to be horizontal or vertical. If you choose coordinate axes that line up with some of your force vectors you will simplify later analysis. Once you have chosen axes, you need to break down all of the force vectors into components along the \(x\), \(y\) and \(z\) directions (see the vectors page in Appendix 1 if you need more guidance on this). Your first equation will be the sum of the magnitudes of the components in the \(x\) direction being equal to zero, the second equation will be the sum of the magnitudes of the components in the \(y\) direction being equal to zero, and the third (if you have a 3D problem) will be the sum of the magnitudes in the \(z\) direction being equal to zero. Collectively these are known as the equilibrium equations. Once you have your equilibrium equations, you can solve them for unknowns using algebra. The number of unknowns that you will be able to solve for will be the number of equilibrium equations that you have. In instances where you have more unknowns than equations, the problem is known as a statically indeterminate problem and you will need additional information to solve for the given unknowns. A 3-pound box (A) rests on top of a 5-pound box (B), which rests on top of a flat surface.Solution A barrel is wedged in a gap shaped like a point-down triangle, with the left side of that triangle making a 45-degree angle with the horizontal and the right side of the triangle making a 30-degree angle to the vertical.Solution A traffic light held in midair by two cables: one horizontal cable on the left <a href=and one on the right raised at 15 degrees above the horizontal." />Solution A wrecking ball rests on a surface slanted at 45 degrees above the whole, with its cable stretched taut and held at a 15 degree angle away from the vertical, slanting towards the supporting surface.Solution A 150-lb barrel (A) is stacked on top of a 200-lb barrel (B), with both placed on a handcart. The cart is tilted so the bottom is 30 degrees above the horizontal.Solution Two soda cans of equal radius, B and C, are lying on <a href=their sides next to each other on a flat surface 9 inches wide. The flat surface is bounded on the left and right by a vertical wall. A third soda can of the same size, A, is stacked on its side on top of B and C." />Solution A skycam, represented as a rectangular box, is drawn on a 3-dimensional coordinate plane and shown being held up by 3 cables. One makes a 10-degree angle above the x-axis in the negative direction, <a href=one makes a 15-degree angle above the x-axis in the positive direction, and one makes a 15-degree angle above the xz plane with its projection onto said plane making a 60-degree angle with the negative z-axis." />Solution A hovering hot-air balloon, attached to the ground by 3 cables, is shown on a 3-dimensional coordinate plane. The balloon is 30 ft above the origin, cable A is attached to the ground 20 ft to the left of the origin, cable B is attached to the ground 30 feet to the right of and 20 feet in front of the origin, and cable C is attached to the ground 20 ft behind the origin.Solution

Video \(\PageIndex<9>\): Worked solution to example problem \(\PageIndex\), provided by Dr. Jacob Moore. YouTube source: https://youtu.be/HQqNGJR3ybQ.

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